APPSC R Y B 50/51 V I φ cos φ = P/S
Andhra Pradesh PSC (APPSC) Assistant Executive Engineer (AEE) Electrical Engineering (Paper-II & Paper-III)

APPSC AEE Electrical Engineering Solved Papers

Master official APPSC Assistant Executive Engineer previous years' solved question papers with comprehensive step-by-step derivations across Electric Circuits & Network Theory, Electromagnetic Fields, Electrical Machines, Power Systems (Transmission, Distribution & Protection), Control Systems, Electrical & Electronic Measurements, Power Electronics & Drives, and Analog & Digital Electronics.

0%
Score Tracker
Live accuracy rate
0
Correct
0
Review
0
Attempted
Filter APPSC AEE Electrical Questions

All APPSC AEE Electrical Solved Papers / All Technical Domains / All Chapters

Marking pattern: +1.00 positive, -0.33 negative marking (Official APPSC 1/3rd Negative Marking Scheme; 150 Questions, 150 Marks).

300 Questions Page 4 of 12
76

A synchronous motor can be used as synchronous condenser when it is

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Synchronous Machines
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
77

If $Z_d$, $X_d$ and $X_q$ are per-phase values of direct axis synchronous impedance, direct axis synchronous reactance and quadrature axis synchronous reactance respectively, then for a non salient-pole synchronous machine

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Synchronous Machines
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
78

In the given circuit, the current is $i(t) = 4 \sin(500t)\text{ A}$. The applied voltage in volts is

Vi(t)10 Ω20 mH
APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Network Theory
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
79

Operating torques in an indicating instrument are

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Electrical Measurements
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
80

In a transformer, the exciting current will be in phase quadrature with the impressed voltage provided

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Transformers
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
81

In a 3-phase synchronous motor, the magnitude of field flux

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Synchronous Machines
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
82

A 3-phase synchronous motor needs dc supply for excitation

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Synchronous Machines
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
83

A synchronous motor operating with normal excitation adjusts to increased load due to increase in

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Synchronous Machines
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
84

A 5 kVA transformer has a turn-ratio of $(N_{1}/N_{2}) = 10$. The impedance of the primary winding is $3 + j5\text{ ohms}$ while that of secondary winding is $0\cdot5 + j0\cdot8\text{ ohms}$. The impedance of the transformer when referred to the primary will be

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Transformers
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
85

In indicating instruments, the springs are mainly used to

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Electrical Measurements
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
86

In the circuit of fig. shown, steady state has been reached with the switch open. The switch is closed at $t = 0$. The current $i$ at $t = 0^{+}$ is

+-6 V1 Ω1 Ω1 H1 Ωi
APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Network Theory
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
87

The function of a starter in a dc motor is

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) DC Machines
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
88

During normal running conditions, the armature current drawn by a dc shunt motor is given by

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) DC Machines
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
89

In a dc machine, the laminated parts are armature and

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) DC Machines
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
90

The direction of shaded pole single phase induction motor can be reversed by

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Induction Motors
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
91

Inverted V-curve of a synchronous motor is

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Synchronous Machines
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
92

A 220 V dc machine has an armature resistance of $1\;\Omega$. If the full-load current is 20 A, the difference in the induced voltage when the machine runs as a motor, and as a generator, is

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) DC Machines
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
93

A Lissajous pattern on an oscilloscope has 5 horizontal tangencies and 2 vertical tangencies. The frequency of the horizontal input is 1000 Hz. What is the frequency of the vertical input?

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Electrical Measurements
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
94

The speed of single phase induction motors can be controlled by

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Induction Motors
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
95

Maximum operating frequency of CRO is mainly governed by its

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Electrical Measurements
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
96

If $V_{th} = 10\text{ V}$, $R_{th} = 2\;\Omega$ and $R_{L} = 3\;\Omega$, then current through $R_{L}$ is

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Network Theory
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
97

In dc machines, the space distribution of air gap flux density wave at no-load is

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) DC Machines
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
98

The flux created by current flowing through the primary winding of a transformer induces emf in

APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Transformers
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
99

In the given circuit, the current flowing in the $2\;\Omega$ resistor is

+-3 volts2 Ω2 Ω+-6 volts2 Ω
APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Network Theory
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof
100

The steady state value of the current in the given circuit is

+-16 volts4 Ω4 H
APPSC AEE Electrical Exam Paper II (Exam Date: 01-07-2012) Network Theory
Technical Evaluation
Click an option to analyze
Select an option on the left to reveal the step-by-step mathematical derivation, phasor relationships, and circuit theorems.
Engineering Solution & Mathematical Proof