Photoelectric Effect & Wave Particle Duality | H C Verma | Solution
1. Visible light has wavelengths in the range of \(400 \,\text{nm}\) to \(780 \,\text{nm}\). Calculate the range of energy of the photons of visible light. Solution: The energy (\(E\)) of a photon is calculated using the formula: $$E = \frac{hc}{\lambda}$$ Given constants: Planck constant (\(h\)): \(6.63 \times 10^{-34} \,\text{J s}\) Speed of light (\(c\)): \(3 …
Photoelectric Effect & Wave Particle Duality | H C Verma | Solution Read More »